Let
.Consider
, that is uk+1= Auk , where
.Because the characteristic polynomial of A is
, the eigenvalues of A are
and
, and the corresponding eigenvectors are
and
. Of course {x1,
x2} are linearly
independent and generate uk.Write u0=c1x1+c2x2, that is
, and it’s easy to solve the coefficients
and
. Hence
u1=c1Ax1+c2Ax2= c1λ1x1+c2λ2x2 ,
… ,
Thus 

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